A) 400 nm and 450 nm
B) 425 nm and 400 nm
C) 400 nm and 425 nm
D) 450 nm and 400 nm
Correct Answer: D
Solution :
Position of nth bright fringe from central maxima is \[\frac{n\lambda D}{d}\]. \[\therefore \] \[\frac{8{{\lambda }_{1}}D}{d}=\frac{9{{\lambda }_{2}}D}{d}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{9}{8}\]which is correct only for option .
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