J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    The elastic energy stored per unit volume in a stretched wire is

    A) \[\frac{1}{2}\]- (Young modulus) (Strain)2

    B)  \[\frac{1}{2}\]- (Stress) (Strain)2

    C) \[\frac{1}{2}\frac{Stress}{Strain}\]

    D)  \[\frac{1}{2}\]- (Young modulus) (Stress)

    Correct Answer: A

    Solution :

                     The energy stored in per unit volume of wire \[({{U}_{V}})\] \[=\frac{1}{2}\times \frac{Fl}{volume}=\frac{1}{2}\times stress\times strain\] \[=\frac{1}{2}\times Y\times {{(strain)}^{2}}=\frac{1}{2Y}{{(stress)}^{2}}\]


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