J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    Assuming that the earth is a sphere of radius RE with uniform density, the distance from its centre at which the acceleration due to gravity a is equal to \[\frac{g}{3}\](g = the acceleration due to gravity on the surface of earth) is

    A) \[\frac{{{R}_{E}}}{3}\]                                   

    B) \[2\frac{{{R}_{E}}}{3}\]

    C) \[\frac{{{R}_{E}}}{2}\]                                   

    D) \[\frac{{{R}_{E}}}{4}\]

    Correct Answer: B

    Solution :

                     Acceleration due to gravity at a depth d is\[g=g\left[ 1-\frac{d}{{{R}_{E}}} \right]\]\[\Rightarrow \]                \[\frac{g}{3}=g\left[ 1-\frac{d}{{{R}_{E}}} \right]\]Or \[d=\frac{2}{3}{{R}_{E}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner