A) \[270{}^\circ C\text{ } and \text{ }530{}^\circ C\]
B) \[270{}^\circ C\text{ } and \text{ }550{}^\circ C\]
C) \[280{}^\circ C\text{ } and \text{ }530{}^\circ C\]
D) \[280{}^\circ C\text{ } and \text{ }550{}^\circ C\]
Correct Answer: A
Solution :
No change in neutral temperature but temperature of inversion is \[{{t}_{i}}=2{{t}_{n}}-{{t}_{c}}\] \[540=2{{t}_{n}}-{{0}^{o}}\] \[{{270}^{o}}C={{t}_{n}}\] \[{{t}_{i}}=2\times 270-10\] \[=540-10={{530}^{o}}C\]
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