J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    Three forces \[{{F}_{1}}{{F}_{2}}\]and \[{{F}_{3}}\]together keep a body in equilibrium. If \[{{F}_{1}}=\text{ }3\text{ }N\]along the positive x-axis, \[{{F}_{2}}=\text{ }4\text{ }N\]along the positive y-axis, then the third force \[{{F}_{3}}\]is

    A)  5 N making an angle \[\theta ={{\tan }^{-1}}\left( \frac{3}{4} \right)\]with the negative y-axis

    B)  5 N making an angle \[\theta ={{\tan }^{-1}}\left( \frac{4}{3} \right)\]with the negative y-axis

    C)  7 N making an angle \[\theta ={{\tan }^{-1}}\left( \frac{3}{4} \right)\] with the negative y-axis

    D)  7 N making an angle \[\theta ={{\tan }^{-1}}\left( \frac{4}{3} \right)\] with the negative y-axis

    Correct Answer: A

    Solution :

                     Resultant,          \[R=\sqrt{{{x}^{2}}+{{y}^{2}}}\] \[R=\sqrt{{{3}^{2}}+{{4}^{2}}}\] \[R=\sqrt{25}=5\,N\] and                        \[\cos \theta =\frac{x}{R}=\frac{3}{5}\]                                 \[\sin \theta =\frac{y}{R}=\frac{4}{5}\] Then                      \[\tan \theta =\frac{y}{x}=\frac{4}{3}\] \[\theta ={{\tan }^{-1}}\left( \frac{4}{3} \right)\]with negative y-axis.


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