J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    The electric field and the potential of an electric dipole vary with distance r as

    A)  \[\frac{1}{r}and\frac{1}{{{r}^{2}}}\]                                       

    B)  \[\frac{1}{{{r}^{2}}}and\frac{1}{r}\]

    C)  \[\frac{1}{{{r}^{2}}}and\frac{1}{{{r}^{3}}}\]                                        

    D)  \[\frac{1}{{{r}^{3}}}and\frac{1}{{{r}^{2}}}\]

    Correct Answer: D

    Solution :

                     Electric field and electric potential at a general point at a distance r from the centre of the dipole is\[{{E}_{g}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{p}{{{r}^{3}}}\sqrt{(3{{\cos }^{2}}\theta +1)}\] and \[{{V}_{g}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{p\cos \theta }{{{r}^{2}}}\]


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