A) 4 : 2 : 1
B) 2 : 2 : 1
C) 1 : 2 : 4
D) 1 : 1 : 1
Correct Answer: B
Solution :
Radius of the path\[r=\frac{\sqrt{2mK}}{qB}\] or \[r\propto \frac{\sqrt{1}}{q}\] \[{{r}_{p}}:{{r}_{d}}:{{r}_{\alpha }}=\frac{\sqrt{1}}{{{q}_{p}}}:\frac{\sqrt{1}}{{{q}_{d}}}:\frac{\sqrt{1}}{{{q}_{\alpha }}}\] \[\frac{1}{1}:\frac{1}{1}:\frac{1}{2}=2:2:1\]
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