J & K CET Medical J & K - CET Medical Solved Paper-2010

  • question_answer
    A wave motion is described by y (x, t) = a sin (kx - \[\omega t\]). Then the ratio of the maximum particle velocity to the wave velocity is

    A)  \[\omega a\]                                   

    B) \[\frac{1}{ka}\]

    C)  \[\frac{\omega }{k}\]                                   

    D)  ka

    Correct Answer: D

    Solution :

                     Maximum particle velocity \[{{({{v}_{p}})}_{\max }}=a\omega \] and wave velocity, \[v=\frac{\omega }{k}\] \[\therefore \]Ratio\[\frac{{{({{v}_{p}})}_{\max }}}{v}=\frac{a\omega k}{\omega }=ka\]


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