question_answer

The fundamental frequencies of an open and a closed tube, each of same length L with v as the speed of sound in air, respectively are

A) \[\frac{v}{2L}and\frac{v}{L}\]                    

B) \[\frac{v}{L}and\frac{v}{2L}\]

C) \[\frac{v}{2L}and\frac{v}{4L}\]                  

D) \[\frac{v}{4L}and\frac{v}{2L}\]

Correct Answer: C

Solution :

                 

Fundamental mode	Fundamental mode
\[{{v}_{1}}=\frac{v}{4l}\]	\[{{v}_{1}}=\frac{v}{{{\lambda }_{1}}}=\frac{v}{2l}\]