J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    In beta minus decay a neutron transforms with the nucleus according to

    A) \[p\to n+{{e}^{+}}+v\] 

    B) \[n\to p+{{e}^{-}}+\overset{-}{\mathop{v}}\,\]

    C) \[n\to p+{{e}^{+}}+\overset{-}{\mathop{v}}\,\]               

    D) \[n\to p+{{e}^{+}}+v\]

    Correct Answer: C

    Solution :

    A beta minus particle\[{{\beta }^{-}}\]is an electron. Emission of\[{{\beta }^{-}}\]involves transformation of a neutron into a proton, an electron and a third particle called an antmeutrino. \[n=p{{+}_{-1}}{{\beta }^{0}}+\overline{v}\] or           \[n\to p+{{e}^{-}}+\overline{v}\]


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