J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    The pH of the solution formed by mixing 20 mL of\[0.05M\,{{H}_{2}}S{{O}_{4}}\]with 5.0 mL of 0.45 M \[NaOH\]at 298 K is

    A)  6                                            

    B)  2

    C)  12                                         

    D)  7

    Correct Answer: C

    Solution :

                    \[0.05\text{ }M\,{{H}_{2}}S{{O}_{4}}=0.05\times 2=0.1\text{ }N\,{{H}_{2}}S{{O}_{4}}\] \[0.45\text{ }M\text{ }NaOH=0.45\times 1=0.45\text{ }N\text{ }NaOH\] \[Meq.\text{ }of\text{ }{{H}_{2}}S{{O}_{4}}=0.1\times 20=2\] \[Meq.\text{ }of\text{ }NaOH=0.45\times 5=2.25\] \[Meq.\text{ }of\text{ }NaOH\text{ }left=2.25-2=0.25\] Hence, resulting solution is alkaline in nature.


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