A) n-hexane
B) 2, 2-dimethylbutane
C) 2, 3-dimethylbutane
D) 3-methylpentane
Correct Answer: C
Solution :
2,3-dimethylbutane has 12 equivalent\[{{1}^{o}}H\] and two equivalent\[{{3}^{o}}H\] hence it gives two constitutionally isomeric monochlorides of molecular formula\[{{C}_{6}}{{H}_{13}}Cl\]. \[\underset{2,3-dimethylbutane}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\xrightarrow[Heat]{C{{l}_{2}},\,Light}\] \[C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}Cl\] \[+C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]
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