J & K CET Medical J & K - CET Medical Solved Paper-2011

The electrons identified by quantum numbers n and ;

(i) \[n=4,l=1,\]

(ii) \[n=4,l=0\]

(iii) \[n=3,l=2\]

and

(iv) \[n=3,l=1\]

can be placed in order of increasing energy as

A) (i) < (ii) < (iii) < (iv)

B) (iv) < (iii) < (ii) < (i)

C) (iv) < (ii) < (iii) < (i)

D) (iv) < (i) < (ii) < (iii)

Correct Answer: C

Solution :

According to (n + 0 rule, the lower the value of (n + 0 for an orbital, the lower is its energy. If two orbitals have the same value of\[(n+l),\] the orbital with lower value of n will have the lower energy. Hence, the order of increasing energy of electron is as

IV < II < III < I
\[\begin{array}{*{35}{l}} n=3 \\ \end{array}\]	\[n=4\]	\[\begin{array}{*{35}{l}} n=3 \\ \end{array}\]	\[n=4\]
\[l=1\]	\[l=0\]	\[l=2\]	\[l=1\]
\[n+l=4\]	\[n+l=4\]	\[n+l=5\]	\[n+l=5\]

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