J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    A radioactive element\[_{92}^{238}M\]emits one alpha particle followed by two beta particles. Then the daughter element formed is

    A)  an isotope         

    B)  an isobar

    C)  an isotone         

    D)  an isodiaphere

    Correct Answer: A

    Solution :

                    \[_{92}^{238}M\xrightarrow[{}]{-\alpha }_{90}^{234}X\xrightarrow[{}]{-\beta }_{91}^{234}Y\xrightarrow[{}]{-\beta }_{92}^{234}Z\] The atomic number of radioactive element \[(_{92}^{238}M)\]and daughter element\[(_{92}^{234}Z)\]is same hence they are isotopes.


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