A) \[Li>C>B>Be\]
B) \[Li>B>C>Be\]
C) \[B>C>Be>Li\]
D) \[Be>C>B>Li\]
Correct Answer: B
Solution :
The order of second ionization energies of Li, Be, B and C are as| Element: | Li > B > C > Be | |||
| \[I{{E}_{2}}\](kJ \[mo{{l}^{-1}}\]): | 7297 | 2427 | 2354 | 1757 |
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