A) Methane
B) Ethane
C) Ethyne
D) Ethene
Correct Answer: C
Solution :
Terminal alkynes have acidic H because\[CH\]bond has ionic character due to resonance \[H-C\equiv CH\underset{{}}{\overset{{}}{\longleftrightarrow}}HC\equiv \overset{-}{\mathop{C}}\,\overset{+}{\mathop{H}}\,\underset{{}}{\overset{{}}{\longleftrightarrow}}\] \[\overset{+}{\mathop{H}}\,-\overset{-}{\mathop{C}}\,\equiv CH\underset{{}}{\overset{{}}{\longleftrightarrow}}\overset{+}{\mathop{H}}\,-\overset{-}{\mathop{C}}\,\equiv \overset{-}{\mathop{C}}\,-\overset{+}{\mathop{H}}\,\] Greater the s-character of carbon atom greater the electronegativity and hence greater the attraction for electrons. Proton release, therefore, is maximum in ethyne \[(HC\equiv CH)\].
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