A) \[\frac{1.227}{\sqrt{v}}mm\]
B) \[\frac{0.1227}{\sqrt{v}}mm\]
C) \[\frac{0.01227}{\sqrt{v}}mm\]
D) \[\frac{0.1227}{\sqrt{v}}\overset{0}{\mathop{A}}\,\]
Correct Answer: A
Solution :
The de-Broglie wavelength\[\lambda =\frac{1.227}{\sqrt{V}}nm\]
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