A) \[\frac{{{p}^{2}}}{2m}\]
B) \[\frac{p}{2m}\]
C) \[\frac{{{v}^{2}}}{2m}\]
D) \[\frac{v}{2m}\]
Correct Answer: A
Solution :
Kinetic energy of particle\[=\frac{1}{2}m{{v}^{2}}\]or \[K=\frac{p}{2m}\] \[[\because p<mv]\]
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