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J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    When the current changes form + 2A to - 3A in 0.05, an emf of 8 V is induced in a coil. The coefficient of self-inductance of the coil is

    A)                  0.2 H                                    

    B)  0.4 H

    C)                  0.8 H                                    

    D)  0.1 H

    Correct Answer: D

    Solution :

                     \[e=L\frac{di}{dt}\] \[8=\frac{L[2-(2)]}{0.05}\] \[8=\frac{L\times 4}{0.05}\] \[L=\frac{8\times 0.05}{4}\] The coefficient of self-inductance, \[L=0.1H\]


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