J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    A car moving with a speed of 50 km/h can be stopped by brakes, over a distance of 6m. If the same car is moving at a speed of 100 km/h, the stopping distance is

    A)                  12 m                                    

    B)  18 m

    C)                  6 m                                       

    D)  24 m

    Correct Answer: D

    Solution :

                     Case I. \[{{v}^{2}}={{u}^{2}}-2as\] \[0={{(50)}^{2}}-2\times a\times \frac{6}{1000}\] \[\frac{2\times a\times 6}{1000}=50\times 50\] \[a=\frac{50\times 50\times 1000}{2\times 6}\] Case II. \[{{v}^{2}}={{u}^{2}}-2as\]                 \[0={{(100)}^{2}}-2\times \frac{50\times 50\times 1000}{2\times 6}\times 5\]                 \[s=\frac{100\times 100\times 6}{50\times 50\times 1000}\]                 \[s=\frac{24}{1000}km\] \[s=24m\]


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