A) Density
B) Volume
C) Mass
D) Radius
Correct Answer: A
Solution :
Nuclear radius \[R={{R}_{0}}{{A}^{1/3}}\] Nuclear volume \[V=\frac{4}{3}\pi {{R}^{3}}=\frac{4}{3}\pi R_{0}^{3}A\] \[Nuclear\text{ }density\text{ }\rho =\frac{mA}{\frac{4}{3}\pi {{({{R}_{0}}{{A}^{1/3}})}^{3}}}\] \[\rho =\frac{m}{\frac{4}{3}\pi {{R}_{0}}}\]where A is the mass number. We can see that density is independent of mass number.
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