A) \[T=\frac{\mathop{v}_{0}^{2}\sin 2\theta }{g}\]
B) \[T=\frac{\mathop{v}_{0}^{2}\sin 2\theta }{2g}\]
C) \[T=\frac{v_{0}^{2}}{g}\]
D) \[T=\frac{2{{v}_{0}}\sin \theta }{g}\]
Correct Answer: D
Solution :
Time of flight, \[T=\frac{2{{v}_{0}}\sin \theta }{g}\]You need to login to perform this action.
You will be redirected in
3 sec