A) 1960 J
B) 196 J
C) 1.96 J
D) 196 k J
Correct Answer: A
Solution :
Given, \[F=20kg-wt=20\times 9.8N\] \[\theta ={{60}^{o}}\] and \[s=20\text{ }m\] Work done \[=F.s\text{ }cos\theta \] \[=20\times 9.8\times 20\times cos\text{ }{{60}^{o}}\]\[=1960J\]You need to login to perform this action.
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