J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    A capacitor of capacitance \[{{C}_{1}}\]is charged to a potential V and then connected in parallel to an uncharged capacitor of capacitance \[{{C}_{2}}.\]The final potential difference across each capacitor will be

    A)                 \[\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]                             

    B) \[\frac{{{C}_{2}}V}{{{C}_{1}}+{{C}_{2}}}\]

    C)                 \[1+\frac{{{C}_{2}}}{{{C}_{1}}}\]                               

    D) \[1-\frac{{{C}_{2}}}{{{C}_{1}}}\]

    Correct Answer: A

    Solution :

                     If two capacitors having capacitance\[{{C}_{1}}\]and\[{{C}_{2}}\] respectively are connected in parallel, then \[{{C}_{eq}}={{C}_{1}}+{{C}_{2}}\] The final potential difference across each capacitor                                 \[V=\frac{{{C}_{1}}V}{{{C}_{1}}{{C}_{2}}}\]


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