2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    The escape velocity of a body on the surface of earth is 11.2 km/s. If the earths mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become

    A)                  5.6 km/s                             

    B)  11.2 km/s

    C)                  44.8 km/s                          

    D)  22.4 km/s

    Correct Answer: D

    Solution :

                     Escape velocity, \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2G\times 2M}{R/2}}\] \[=2\sqrt{\frac{2GM}{R}}=2\times 11.2\,km/s\] \[=22.4\text{ }km/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner