A) 1
B) 2
C) 0
D) 3
Correct Answer: B
Solution :
The electronic configuration of\[{{C}_{2}}\]molecule is as \[{{C}_{2}}=\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\pi 2p_{y}^{2}=\pi 2p_{z}^{2}\] \[Bond\text{ }order=\frac{{{N}_{b}}-{{N}_{a}}}{2}\] \[=\frac{8-4}{2}\] \[=2\]
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