question_answer

The hybridization involved in\[PC{{l}_{5}}\]is

A)  \[s{{p}^{3}}d\]                                

B) \[s{{p}^{3}}{{d}^{2}}\]

C)  \[{{d}^{2}}s{{p}^{2}}\]                                 

D) \[s{{p}^{3}}\]

Correct Answer: A

Solution :

                In\[PC{{l}_{5}}\]five chlorine atoms directly attached to central atom and it has no lone pairs and no single electrons hence\[PC{{l}_{5}}\]has\[s{{p}^{3}}{{d}^{2}}\]hybridization.