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J & K CET Medical J & K - CET Medical Solved Paper-2011

  • question_answer
    The reaction\[A+B\xrightarrow{{}}C+D+40\text{ }kJ\]has an activation energy of 18 kJ. Then the activation   energy   for   the   reaction\[C+D\xrightarrow{{}}A+B\]is

    A)  58 kJ                                    

    B) \[-40kJ\]

    C) \[-18\text{ }kJ\]                               

    D)  22 kJ

    Correct Answer: A

    Solution :

                    (a) \[A+B\xrightarrow{{}}C+D+40\text{ }kJ\] \[\because \] Activation energy for the forward reaction, \[A+B\xrightarrow{{}}C+D=18kJ\] \[\therefore \] Activation energy for the reverse reaction, \[C+D\xrightarrow{{}}A+B=40+18=58\text{ }kJ\]


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