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J & K CET Medical J & K - CET Medical Solved Paper-2012

  • question_answer
    A first order reaction has a rate constant\[k=3.01\times {{10}^{-3}}/s\]. How long it will take to decompose half of the reaction?

    A)  2.303 s         

    B)  23.03 s

    C)  230.23 s        

    D)  2303 s

    Correct Answer: C

    Solution :

     \[k=3.01\times {{10}^{-3}}{{s}^{-1}}\] \[{{t}_{1/2}}=?\] \[k=\frac{0.693}{{{t}_{1/2}}}\] (tor a first order reaction) \[\therefore \] \[{{t}_{1/2}}=\frac{0.693}{k}\] \[=\frac{0.693}{3.01\times {{10}^{-3}}}\] \[=230.23\,s\]


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