A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[{{C}_{2}}He\]
D) \[{{C}_{2}}{{H}_{2}}B{{r}_{2}}\]
Correct Answer: C
Solution :
The\[CH\]bond distance is the longest in \[{{C}_{2}}{{H}_{6}}\]because the hybrid orbitals of carbon involved in overlapping with 1s orbital of hydrogen is\[s{{p}^{3}}\].
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