question_answer

A bar magnet is placed upright on a floor (so that the axis of the magnet is vertical). A copper ring is held above the magnet, with its plane horizontal and released. The copper ring falls in such a manner that its axis always coincides with that of/ the magnet. What will be the acceleration with which the ring will fall? Acceleration due to gravity is\[10\text{ }m/{{s}^{2}}\].

A)  \[10\text{ }m/{{s}^{2}}\]

B)  less than\[10\text{ }m/{{s}^{2}}\]

C)  more than\[10\text{ }m/{{s}^{2}}\]

D)  the answer will depend upon which pole of the magnet is up