A) paramagnetic
B) diamagnetic
C) ferromagnetic
D) an even electron molecule
Correct Answer: A
Solution :
The molecule NO is paramagnetic. There is a unpaired electron on the nitrogen and it is an odd electron molecule. Alternately we can say it is a free radical and hence is highly reactive. \[\bullet \overset{\bullet \,\bullet }{\mathop{\text{N}}}\,=\underset{\bullet \,\bullet }{\overset{\bullet \,\bullet }{\mathop{\text{O}{}_{\bullet }^{\bullet }}}}\,\]
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