A) 1.35
B) 0.5
C) 3.7
D) 1.85
Correct Answer: C
Solution :
\[{{[{{H}^{+}}]}_{HCOOH}}=\sqrt{{{K}_{a}}.C}\] \[=\sqrt{2\times {{10}^{-4}}\times 0.0002}\] \[pH=-log[{{H}^{+}}]=-\log (2\times {{10}^{-4}})\] \[=3.69-3.7\]You need to login to perform this action.
You will be redirected in
3 sec