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J & K CET Medical J & K - CET Medical Solved Paper-2012

  • question_answer
    The effective atomic number for \[{{[Rh{{({{H}_{2}}O)}_{6}}]}^{3+}}\] (at. no. for Rh is 45) is

    A)  42             

    B)  45

    C)  48             

    D)  54

    Correct Answer: D

    Solution :

     The   effective   atomic   number   for\[{{[Rh{{({{H}_{2}}O)}_{6}}]}^{3+}}\](atomic no. of\[Rh=45\]) is 54. Because rhodium is in oxidation state \[x+6\times 0=+3\] \[x=+3\] \[R{{h}^{3+}}=45-3=42\] 42+12 electrons from 6 ligands\[({{H}_{2}}O)\] =54 electrons.


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