A) 0
B) 1.73 BM
C) 2.83BM
D) 4.9BM
Correct Answer: D
Solution :
The spin only magnetic moment of \[{{[Cr{{F}_{6}}]}^{4-}}\] \[x-6=-4\] \[x=+2\] \[Cr(+2)=[Ar]3{{d}^{4}}\] \[n=4\] (number of unpaired electrons) Magnetic moment \[=\sqrt{n(n+2)}=\sqrt{4(4+2)}\] \[=\sqrt{24}=4.9BM\]You need to login to perform this action.
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