A) 14
B) 8
C) 6
D) 4
Correct Answer: D
Solution :
In a fee lattice, Contribution of 8 atoms at comers \[=8\times \frac{1}{8}=1\] Contribution of 6 face centred atoms \[=6\times \frac{1}{2}=3\] \[\therefore \]Total number of atoms per unit cell \[=1+3=4\]You need to login to perform this action.
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