A) \[54{}^\circ C\]
B) \[327{}^\circ C\]
C) \[1200{}^\circ C\]
D) \[927{}^\circ C\]
Correct Answer: D
Solution :
Mean velocity of gas molecules \[v=\sqrt{\frac{8RT}{\pi T}}\] \[v\propto \sqrt{T}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{300}{{{T}_{2}}}}\] \[\frac{{{v}_{1}}}{2{{v}_{1}}}=\sqrt{\frac{300}{{{T}_{2}}}}\] \[\frac{1}{4}=\frac{300}{{{T}_{2}}}\] \[{{T}_{2}}=1200\,K\] \[=1200-273\] \[=927{}^\circ C\]
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