A) \[N{{F}_{3}}\]
B) \[N{{H}_{3}}\]
C) \[C{{H}_{4}}\]
D) \[PC{{l}_{3}}\]
Correct Answer: B
Solution :
\[N{{H}_{3}}\]has the maximum dipole moment, i.e., 1.46 D. This is because, in case of NH3 the orbital dipole due to lone pairs is in the same direction as the resultant dipole moment of \[N-H\]bonds.
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