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J & K CET Medical J & K - CET Medical Solved Paper-2013

  • question_answer
    A hollow sphere of radius 0.1 m has a charge of\[5\times {{10}^{-8}}C\]. The potential at a distance of 5 cm from the centre of the sphere is \[\left( \frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}N{{m}^{2}}{{C}^{-2}} \right)\]

    A)  4000V            

    B)  4500V

    C)  5000V            

    D)  6000V

    Correct Answer: B

    Solution :

     Potential \[V=\frac{Q}{4\pi {{\varepsilon }_{0}}r}\] Given, \[Q=5\times {{10}^{-8}}C,\frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}},R=0.1\,m\] \[V=\frac{5\times {{10}^{-8}}\times 9\times {{10}^{9}}}{0.1}\] \[=\frac{450}{0.1}=4500\,V\]


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