A) 2.71 V
B) 2.03 V
C) \[-2.71\text{ }V\]
D) \[-2.03V\]
Correct Answer: A
Solution :
Given, \[E_{{{A}^{2+}}/A}^{0}=0.34V,E_{{{x}^{2+}}/x}^{0}=-2.37\,V\] Cell voltage\[=E_{cathode}^{0}-E_{Anode}^{0}\] \[=0.34-(-2.37)=2.71V\]You need to login to perform this action.
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