A) \[0.2\times {{10}^{-3}}m/s\]
B) \[0.4\times {{10}^{-4}}m/s\]
C) \[0.68\times {{10}^{-4}}m/s\]
D) \[7\times {{10}^{-4}}m/s\]
Correct Answer: C
Solution :
\[{{V}_{d}}=\frac{I}{\pi Ae}\] Given, \[I=2A,n=5.86\times {{10}^{28}}{{m}^{-3}},\] \[A=\pi {{r}^{2}}=\pi {{(0.1\times {{10}^{-2}})}^{2}},e=1.6\times {{10}^{-19}}C\] \[\therefore \] \[{{v}_{d}}=0.68\times {{10}^{-4}}m/s\]
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