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J & K CET Medical J & K - CET Medical Solved Paper-2013

  • question_answer
    The temperature coefficient of the resistance of a wire is 0.00125 per\[{}^\circ C\]. At 300 K its resistance is\[1\,\Omega \]. The resistance of wire will be\[2\,\,\Omega \]at

    A)  1154K            

    B)  1100K

    C)  1400 K            

    D)  1127K

    Correct Answer: D

    Solution :

     Note None of the four options are correct, through option [d] is close to correct answer. \[{{R}_{t}}={{R}_{0}}(1+\alpha t)\] \[1={{R}_{0}}(1+0.00125\times 27)\]       ...(i) \[2={{R}_{0}}(1+0.00125\times t)\]         ...(ii) From Eqs. (i) and (ii) \[t=848{}^\circ C=1121K\]


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