A) \[0.3\text{ }G\text{ }and\text{ }\delta =30{}^\circ \]
B) \[0.4\text{ }G\text{ }and\text{ }\delta =40{}^\circ \]
C) \[0.5\text{ }G\text{ }and\text{ }\delta =50{}^\circ \]
D) \[0.6\text{ }G\text{ }and\text{ }\delta =60{}^\circ \]
Correct Answer: D
Solution :
\[B=\sqrt{B_{H}^{2}+B_{V}^{2}}\]and\[\tan \delta =\frac{{{B}_{V}}}{{{B}_{H}}}\] Given, \[{{B}_{H}}=0.39\,G,{{B}_{V}}=0.52\,G\] \[{{B}_{E}}=\sqrt{{{(0.30)}^{2}}+{{(0.52)}^{2}}}=\sqrt{0.36}=0.6\] and\[\delta ={{\tan }^{-1}}\frac{{{B}_{V}}}{{{B}_{H}}}={{\tan }^{-1}}\frac{0.52}{0.3}=60{}^\circ \]
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