A) 24 g of magnesium
B) 12 g of carbon
C) 24 g of carbon
D) 12 g of magnesium
Correct Answer: D
Solution :
Number of atoms in 40 g of\[Ca=6.022\times {{10}^{23}}\] (Avogadros number) \[\therefore \]Number of atoms in 20 g of Ca \[=\frac{6.022\times {{10}^{23}}\times 20}{40}=3.011\times {{10}^{23}}\] Like this \[\because \]Number of atoms in 24 g of Mg \[=6.022\times {{10}^{23}}\] \[\therefore \]Number of atoms in 12 g of Mg \[=\frac{6.022\times {{10}^{23}}\times 12}{24}\] \[=3.011\times {{10}^{23}}\]
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