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J & K CET Medical J & K - CET Medical Solved Paper-2013

  • question_answer
    The\[{{[OH]}^{-}}\]in a solution is\[1\text{ }mol\text{ }{{L}^{-1}}\]. The pH of the solution is

    A)  1       

    B)  0      

    C)  14     

    D)  \[{{10}^{-14}}\]

    Correct Answer: C

    Solution :

     Given, \[[O{{H}^{-}}]=1\,mol\,1\text{ }{{L}^{-1}}\] So, we know that \[pOH=-log[O{{H}^{-}}]\] \[pOH=-log1=0\] \[\because \] \[pH+pOH=14\] \[\therefore \] \[pH=14-0=14\]


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