A) \[-437kJ\]
B) 135kJ
C) \[-135\text{ }kJ\]
D) None of these
Correct Answer: C
Solution :
According to available data (i)\[{{C}_{2}}{{H}_{4}}(g)+3{{O}_{2}}(g)\xrightarrow[{}]{{}}2C{{O}_{2}}(g)+2{{H}_{2}}O(l)\] (ii)\[{{C}_{2}}{{H}_{6}}(g)+\frac{7}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}2C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] \[\Delta H=-1566\,kJ\] (iii) \[{{H}_{2}}(g)+\frac{7}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}{{H}_{2}}O(l);\] \[\Delta H=-286\,kJ\] We aim at\[{{C}_{2}}{{H}_{4}}(g)+{{H}_{2}}(g)\xrightarrow[{}]{{}}{{C}_{2}}{{H}_{6}}(g);\]\[\Delta H=?\]Eq. (i) + Eq. (iii) - Eq. (ii) and the correct \[\Delta H\]value is \[=(-1415)+(-286)-(-1566)=-135\text{ }kJ\]
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