A) Between 2 and 4 in all cases
B) Between 0 and 1 in all cases
C) 1 in case of chemisorptions
D) 1 in case of physical adsorption
Correct Answer: B
Solution :
Freundlich adsorption isotherm is given as \[\frac{x}{m}=k{{p}^{1/n}}\] Or \[\log \frac{x}{m}=\log k+\frac{1}{n}\log p\] Graph between\[\log \frac{x}{m}\]and\[log\text{ }p\]is a straight line with slope\[\frac{1}{n}\]and intercept log k. Thus, value of\[\frac{1}{n}\]lies between 0 and 1 in all cases.
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