A) 0.1
B) 0.01
C) 0.2
D) 0.02
Correct Answer: D
Solution :
So percentage change in length of wire \[=\frac{\Delta l}{l}\times 100%\] \[\frac{\Delta l}{l}\times 100=2%\] \[\frac{\Delta l}{l}=\frac{2}{100}=0.02\]
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