A) \[s{{p}^{3}}\]
B) \[s{{p}^{2}}\]
C) \[sp\]
D) None of these
Correct Answer: A
Solution :
\[C{{H}_{4}}\] \[H\overset{\sigma }{\mathop{-}}\,\underset{\begin{smallmatrix} |\sigma \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ |\sigma \end{smallmatrix}}{\mathop{C}}}\,\overset{\sigma }{\mathop{-}}\,H\] Here number of sigma bonds = 4 therefore, type of hybridisation\[=s{{p}^{3}}\]
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