A) 0.50 and 1020kHz
B) 0.66 and 1020kHz
C) 0.50 and 980 kHz
D) 0.66 and 980 kHz
Correct Answer: A
Solution :
Modulation index\[(\mu )=\frac{{{A}_{m}}}{{{A}_{C}}}\] \[=\frac{15}{30}=\frac{1}{2}\] Frequency of upper side band\[=({{f}_{c}}+{{f}_{m}})\] \[=1000+20=1020\text{ }kHz\]
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